Answer:
x=[tex]\sqrt{220}[/tex]
Step-by-step explanation:
Since this is a right angle triangle, and we have two lengths already found, we can use pythagoras to find x.
We know that
a²+b²=c²
Where a, and b are the smaller lengths (the adjacent and opposite), and C is always the longest one (the hypotenuse).
In this case,
x=a
b=6
c=16
So to plug these into the equation, we get:
x²+6²=16²
To isolate x,
we get:
x²=16²-6²
x=[tex]\sqrt{16^2-6^2}[/tex]
[tex]x=\sqrt[]{220}[/tex]
