Hello haohaoxNienie!
[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]
Use the remainder theorem to determine whether x = - 4 is a solution of x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8.
[tex] \large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}[/tex]
Refer to the attached picture.
Steps :-
- First find the divisor using the given information (x = - 4).
- Now, divide x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8 by x + 4.
- We'll get the remainder as 0.
- Using the remainder theorem & solving it, we'll get LHS & RHS as 0.
- Hence proved.
Answer :- Yes, x = - 4 is a solution of x⁶ + 5x⁵ + 5x⁴ + 5x³ + 2x² - 10x - 8.
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Hope it'll help you!
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