Answer:
sample size = 10
it is not practical because we can't draw a conclusion for a complete population based on the sample size of 10 people
Step-by-step explanation:
mean = 100
standard deviation = sigma = 10
confidence level = 99%
The z-score for 99% confidence level = z = 2.58
mean IQ is within 8 IQ points so:
error = E = 8
sample size = n (we don't know it)
Since the distribution is normal, we can use the formula of margin of error for z-distribution to calculate the missing sample size:
[tex]E = z * \frac{sigma}{\sqrt{n} } \\\sqrt{n} = z * \frac{sigma}{E} \\\\\sqrt{n} = 2.58*\frac{10}{8} \\\\\sqrt{n} = \frac{25.8}{8} \\\\n = (\frac{25.8}{8} )^{2}\\n = 10.4\\[/tex]
next integer rounded is 10