Answer:
First get the time in the air from
h = gt2/2 ⇒
t = √(2h/g)
Plug in
h = 100 m
g = 9.8 m/s2
and get t in seconds. Then multiply t by the constant horizontal speed.
x = vt
Plug in
v = 40 m/s
t = ? (result from above)
and get x in meters.
(b)
Vertical speed:
v(t) = v0 + gt
Plug in
v0 = 0
g and t from above
and get v(t) in m/s.
(c) It is the same as the initial velocity when released, which is 40 m/s.
(d) The horizontal component is the same as the answer for part (c). The vertical component is the result for part (b), in the downward direction.
