The time of motion or time spent in air by the baseball is 7.76 seconds.
The maximum height attained by the baseball is 73.67 m.
The given parameters;
- initial velocity of the baseball, u = 38 m/s
The time of motion of the baseball is calculated using the first kinematic equation as follows;
v = u - gt
where;
- t is the time to reach maximum height
- v is the final velocity of the ball at the maximum height = 0
0 = u -gt
gt = u
[tex]t = \frac{u}{g} \\\\\t = \frac{38}{9.8} \\\\t = 3.88 \ s[/tex]
The time spent in the air = time of entire motion = 2(3.88 s) = 7.76 seconds
The maximum height attained by the ball is calculated using the second kinematic equation as shown below;
[tex]h = ut -\frac{1}{2} gt^2\\\\h = (38\times 3.88)\ - \ (0.5 \times 9.8 \times 3.88^2)\\\\h = 73.67 \ m[/tex]
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