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Hello AljakeVillena!

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

Given,

  • mass of crate = 50 kg
  • Force you pull it with = 450 N
  • Frictional force = 250 N
  • Acceleration = ?

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Let's first find the total force/net force acting on the crate. The total force will be :-

  • 450 N - 250 N = 200 N.

We subtracted the forces because both the forces act on opposite directions.

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Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..

  • Acceleration = Force/mass
  • a = F/m
  • a = 200/50
  • a = 4 m/s²

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So, the acceleration of the crate is 4 m/s².

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Hope it'll help you!

ℓu¢αzz ッ

Force is mass times acceleration for linear motion. The acceleration of the crate in considered situation is  4 N/kg

How to calculate the acceleration from mass and force given?

If net force is applied on an object of mass "m" in linear direction, with magnitude F, then, acceleration of that object is:

[tex]a = \dfrac{\rm F}{\rm m} \: \rm[/tex]

(assuming one dimensional motion, force is also in that dimension).

Here, it is given that crate's mass m = 50kg

Force pulling the crate = 450 N (positive since it is in direction of motion (horizontal)

Force resisting the crate = -250 N (negative since it is opposite to the direction of motion).

Net force on crate = 450 N + (-250 N ) = 200N (positive, thus, in the direction of motion).

Acceleration of the crate = 200/50 = 4 N/kg

Thus,  the acceleration of the crate in considered situation is  4 N/kg

Learn more about acceleration here:

https://brainly.com/question/1046166

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