UVB photons, with wavelengths between 270 nm and 300 nm, have energies in the range of 6.63 × 10⁻¹⁹ J - 7.37 × 10⁻¹⁹ J.
UVB rays have wavelengths (λ) between 270 nm and 300 nm. We can calculate the energy (E) associated with each wavelength using the Planck-Einstein's relation.
[tex]E = \frac{h \times c}{\lambda }[/tex]
where,
The energy associated with a wavelength of 270 nm is:
[tex]E = \frac{h \times c}{\lambda } = \frac{(6.63 \times 10^{-34}J.s ) \times (3.00 \times10^{8}m/s )}{270 \times 10^{-9}m } = 7.37 \times 10^{-19} J[/tex]
The energy associated with a wavelength of 300 nm is:
[tex]E = \frac{h \times c}{\lambda } = \frac{(6.63 \times 10^{-34}J.s ) \times (3.00 \times10^{8}m/s )}{300 \times 10^{-9}m } = 6.63 \times 10^{-19} J[/tex]
UVB photons, with wavelengths between 270 nm and 300 nm, have energies in the range of 6.63 × 10⁻¹⁹ J - 7.37 × 10⁻¹⁹ J.
Learn more: https://brainly.com/question/18013128
