Answer:
Explanation:
let's use kinematics to solve for max height above the hand.
At the top of its arc, the sword has zero vertical velocity.
v² = u² + 2as
s = (v² - u²)/2a
s = (0² - 5.0²) / (2(-9.8))
s = 1.2755...m
call it 1.3 m
to this we must adjust for the height of the hand at release which is
18.0 + 1.0 = 19.0 m above ground
19.0 + 1.3 = 20.3 m above ground
