You are an electrician working in an industrial plant. A circuit contains eight incandescent lamps connected in series across 480 volts. One lamp has burned out, and you must determine which one is defective. You have available a voltmeter, ammeter, and ohmmeter. Which meter would you use to determine which lamp is defective in the shortest possible time? Explain how you would use this meter and why.

Respuesta :

The burnt out bulb is located between two points in the circuit that have a

discontinuity.

  • The meter that can determine the defective lamp in the shortest possible time is the ohmmeter
  • The ohmmeter can be used iteratively to determine the defective bulb because the ohmmeter checks for continuity between two points and the process is repeated to locate the burned out bulb.

Reasons:

The process and steps to determine the lamp that has burned out;

The given arrangement of the bubs = Series arrangement

Therefore;

A burn out of a bulb, causes a discontinuity by opening the circuit and to current flow.

The meter to use is that determine the defective lamp is one that checks for discontinuity, or an open circuit, which is the presence of infinite resistance, which requires a resistance meter;

Therefore, the ohmmeter (resistance meter) is the best meter to use

 

To determine the defective bulb;

  • Step 1: Switching off the power source or switch of the bulbs
  • Step 2: Place the leads of the ohmmeter from one end of the circuit to after the middle bulb in the series, which is  between the 4th and the 5th bulb
  • Step 3: Check for continuity on the ohmmeter
  • Step 4: If there is continuity, repeat the test on the other half of the circuit.
  • Step 5: If there is discontinuity, repeat the test across each pair of adjacent bulbs within the first half, to find the burnt out bulb.
  • Replace the bulb across which there is a discontinuity and switch on the power source to test the the circuit.

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