Answer:
Ar.ofΔPST
=
4
9
Step-by-step explanation:
In figure ST || QR
and PS= 3 cm & RS= 4cm
In ΔPST & PQR
QPR=∠TPS [Common]
∠PRQ=∠PST [corresponding]
ΔPQR∼ΔPST [AA similarity]
Now
In similar triangles ratios of the area of triangles is equal to the ratio of the square of corresponding sides.
Ar. ofΔPRQ
Ar.ofΔPST
(
3+4
3
)
2
=
49
9
Hence [
Ar.ofΔPRQ
Ar.ofΔPST
=
49
9
]
