One of the legs of a right triangle is twice as long as the other, and perimeter of the triangle is 28. Find the lengths of all three sides, to three decimal places

Respuesta :

Step-by-step explanation:

One leg is x, the second leg is 2x and the hypotenuse is:

  • h = [tex]\sqrt{x^2+(2x)^2} =\sqrt{5x^2} =x\sqrt{5}[/tex]

Perimeter is:

  • x + 2x + x√5 = 28
  • x(3 + √5) = 28
  • x = 28/(3 + √5) ≈ 5.348

The sides are:

  • 5.348,
  • 2*5.348 = 10.696
  • 5.348*√5 = 11.958