Referring to the Fig. in Question #40, find the unknown
length Y.

Answer:
tan30°=7/x
[tex] \frac{1}{ \sqrt{3} } = \frac{7}{x } \\ x = 7 \sqrt{3} [/tex]
cos30°=x/y
[tex] \frac{ \sqrt{3} }{2} = \frac{7 \sqrt{3} }{y} \\ \\ 7 \sqrt{3} \times 2 = \sqrt{3} \times y \\ \frac{7 \sqrt{3 } \times 2}{ \sqrt{3} } = y \\7 \times 2 = y \\ 14 = y[/tex]
tell me if it's wrong.