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25-10-2021
Mathematics

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solve the following system using substitution y=x^2+8x+12, y=-2x-13

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VirαtKσhli VirαtKσhli

25-10-2021

Step-by-step explanation:

Given equations :-

y = x²+ 8x + 12
y = 2x - 13

Substitute (2) in (1) :-

2x - 13 = x² + 8x +12
x² + 8x + 12 - 2x + 13 = 0
x² + 6x + 25 = 0
x = -6±√6²-4*1*25 /2*1
x = -6 ±√36-100/2
x = -6±√-64 / 2
x = -6 ± 8i / 2
x = -3 ±4i

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