Need help confused rn

The exterior angle property of a triangle
[tex] \Large\begin{gathered} {\underline{\boxed{ \rm {\red{y \: + \: 45 \degree \: = \: 100 \degree}}}}}\end{gathered}[/tex]
Now , solving this liner equation
[tex]{{ \large{ \purple{ \rm{{↬}}}}}} \rm \large \: \: \large \rm \: y \: + \: 45 \degree \: = \: 100 \degree[/tex]
[tex]{{ \large{ \purple{ \rm{{↬}}}}}} \rm \large \: \: \large \rm \: y \: = \: 100 \degree \: - \: 45 \degree \:[/tex]
[tex]{{ \large{ \purple{ \rm{{↬}}}}}} \rm \large \: \: \large \rm \: y \: = \: 55 \degree[/tex]
Answer:
Your answer is Y = 55°.
Step-by-step explanation:
x = 180 - 100
x = 80
80+45 = 125
180-125 = 55
Hope this helps!