The equation is:
I=100+12J+5T+7S+5H-8M
The given information is that I=197, J=5, T=5, H=3, and M=3, and we’re trying to solve for the amount of shorts (S) he sold.
We can plug in the variables into the equation:
(197)=100+12(5)+5(5)+7S+5(3)-8(3)
After simplification:
197=100+60+25+7S+15-24
We can add/subtract the constants:
197=100+60+25+7S+15-24
We will add/subtract the constants:
197=176+7S
We will subtract 176 from both sides of the equation to cancel it out and isolate 7S:
197-176=176-176+7S
21=7S
We will divide 7 from both sides of the equation to cancel it out and isolate S:
21/7=7S/7
3=S or S=3 with the symmetric property of Equality applied.
Therefore, he sold 3 pairs of shorts