[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
Let's solve ~
Using first equation we get,
- [tex] {a}^{x} = {b}^{y} [/tex]
[tex]a = \sqrt[x]{ {b}^{y} } [/tex]
- [tex]a = {b}^{ \frac{y}{x} } [/tex]
now, plug the value of a in other equation ~
- [tex]a {}^{y} = b {}^{x} [/tex]
- [tex]( {b}^{ \frac{y}{x} } ) {}^{y} = {b}^{x} [/tex]
- [tex]{(b) }^{ \frac{y}{x} \times y} = {b}^{x} [/tex]
- [tex] {(b)}^{ \frac{ {y}^{2} }{x} } = {b}^{x} [/tex]
- [tex] \dfrac{ {y}^{2} }{x} = x[/tex]
- [tex] {y}^{2} = {x}^{} \times x[/tex]
- [tex] {y}^{2} = {x}^{2} [/tex]
I hope it helps ~
