The magnitude of the net force is 50 Newtons. While its direction is downward because of the negative sign in the answer.
Given that three forces are being exerted on a common object.
Two of the forces are acting downward with values of 20 N and 45 N respectively. The third force (15 N) is being exerted upward on the same object.
Since the three forces are acting both vertically upward and vertically downward, the sum of the three forces should be equal to zero if they are in equilibrium
Let the vertically upward force be positive while vertically downward forces be negative.
Net force = -20 -45 + 15
Net force = - 50 N
The magnitude of the net force is 50 Newtons. While its direction is downward because of the negative sign in the answer.
Below is the free body diagram
∧
| | | |
| + | - | = |
| | | |
|
∨ | |
|
∨ |
|
∨
The magnitude and direction of the net force acting on the object are:
Magnitude: 50 N
Direction: downward
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