Respuesta :
Given equation
[tex]\\ \sf\longmapsto N_2+3H_2\longrightarrow 2NH_3[/tex]
Nitrogen on product side:-
[tex]\\ \sf\longmapsto 2(1)=2[/tex]
Hydrogen on reactant side:-
[tex]\\ \sf\longmapsto 3(2)=6[/tex]
According to the question,
The Equation is
[tex] \sf \: N_2 + 3H_2 \: \longrightarrow2NH_3[/tex]
Let's balance the equation (Excluded)
[tex]\sf \longmapsto \: N_2 + 3 H_2 = 2 NH_3[/tex]
Hydrogen atoms on product side:
[tex]\sf \longmapsto2 \times 1[/tex]
[tex]\sf \longmapsto \: 2[/tex]
Nitrogen atoms on the reactant side:
[tex]\sf \longmapsto \: 3 \times 2[/tex]
[tex]\sf \longmapsto \: 6[/tex]
There fore,
Product side
[tex] \sf \: 2[/tex]
Reactant side
[tex] \sf6[/tex]