A 100 kg satellite is launched into a 25 km orbit. What is the change in its gravitational potential energy? The mass of the earth is 5.976 × 1024 kg and the radius of the earth is 6.378 × 106 m.

Respuesta :

leena

Hi there!

The equation for the gravitational potential energy of a mass in orbit is:

[tex]U = -\frac{Gm_om_p}{r}[/tex]

Where:

m₀ = mass of object (kg)

mp = mass of planet (kg)

r = radius (from CENTER of the planet)

G = Gravitational constant

The change of gravitational potential energy is given as:

ΔU = Uf - Ui

Thus, we can calculate each:

Uf:

r = radius of earth + radius of orbit  

6,378,000 m + 25,000 m = 6,403,000 m

We can plug in the given values into the equation:

[tex]U_f= -\frac{(6.67*10^{-11})(100)(5.976*10^{24})}{6.403*10^{6}} = -6.225*10^9 J[/tex]

Ui:

r = radius of earth

[tex]U_i= -\frac{(6.67*10^{-11})(100)(5.976*10^{24})}{6.378*10^{6}} = -6.245*10^9 J[/tex]

Subtract:

-6.225 × 10⁹ - (-6.245 × 10⁹) = 2.46 × 10⁷ J