Answer:
[tex] \huge{ \boxed{y = - \frac{1}{3} x + 1}}[/tex]
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the graph to find the equation of the line we must first find the slope
The slope of a line given two points can be found by using the formula
[tex]m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\[/tex]
where
(x1 , y1) and (x2 , y2) are the points
Using the points (-6 , -3) and (6,-7) we have
[tex]m = \frac{ - 7 - - 3}{6 - - 6} = - \frac{4}{12} = - \frac{1}{3} \\ [/tex]
Next we use the slope that has been found and one of the points to find the equation of the line
To find an equation of a line when given the slope and a point we use the formula
y - y1 = m(x - x1)
where
m is the slope
( x1 , y1) is the point
From the question using slope -1/3 and point (-6,3) we have
[tex]y - 3 = - \frac{1}{3} (x - - 6) \\ y - 3 = - \frac{1}{3} (x + 6) \\ y - 3 = - \frac{1}{3} x - 2 \: \: \: \\ y = - \frac{1}{3} x - 2 + 3 \: \: [/tex]
The equation of the line in slope-intercept form is
[tex]y = - \frac{1}{3} x + 1 \\ [/tex]
Hope this helps you
