Mamadou is flying a kite, holding his hands a distance of 2.75 feet above the ground and letting all the kite’s string play out. He measures the angle of elevation from his hand to the kite to be 27 ∘ ∘ . If the string from the kite to his hand is 75 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.

Since the angle of elevation of the kite is 27° and the length of the kite's string is 75 ft long, the length of string, height of kite above Mamadou's hand and the horizontal distance between Mamadou and the kite form a right-angled triangle, with hypotenuse side, length of string of kite and opposite side, height of kite above Mamdou's hand, we have that

sin27° = x/75

Making x subject of the formula, we have

x = 75sin27

x = 75 × 0.4540

x = 34.05 ft

Since Mamadou's hand above the ground is y = 2.75 ft, the height of the kite above the ground, h = x + y

Substituting the values of the variables into the equation, we have

h = x + y

= 34.05 ft + 2.75 ft

= 36.8 ft

The height of the kite above the ground is 36.8 ft

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