Answer:
Explanation:
the general form of the position equation with constant acceleration is
s = s₀ + v₀t + ½at²
where
s = position at time = t
s₀ = original position with respect to the selected origin
v₀ = velocity at t = 0
a = constant acceleration
comparing to the equation
x = + at + bt²
shows that
s₀ = 0
v₀ = a
½a = b
a = 2b
acceleration will be twice the b value
