Using the z-distribution, it is found that since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.
At the null hypothesis, it is tested if the mean length of jail time is still of 2.5 years, that is:
[tex]H_0: \mu = 2.5[/tex]
At the alternative hypothesis, it is tested if it has increased, that is:
[tex]H_1: \mu > 2.5[/tex]
We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
The parameters are:
For this problem, the values of the parameters are: [tex]\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26[/tex]
Hence, the value of the test statistic is:
[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}[/tex]
[tex]z = 1.7[/tex]
The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, is of [tex]z^{\ast} = 1.645[/tex]
Since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.
A similar problem is given at https://brainly.com/question/24166849