Respuesta :
The specific heat capacity of a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat is 0.389 J/g°C.
HOW TO CALCULATE SPECIFIC HEAT CAPACITY
The specific heat capacity of a substance can be calculated by using the following expression:
Q = mc∆T
Where;
- Q = quantity of heat absorbed or released
- m = mass of substance
- c = specific heat capacity
- ∆T = change in temperature
According to this question, a 13.5-g sample of zinc heated from 24.2∘C to 83.6 ∘C absorbs 312 J of heat. The specific heat is as follows:
312 = 13.5 × c × (83.6 - 24.2)
312 = 801.9c
c = 312 ÷ 801.9
c = 0.389
Therefore, the specific heat capacity of a 13.5-g sample of zinc heated from 24.2 ∘C to 83.6 ∘C that absorbs 312 J of heat is 0.389 J/g°C.
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