contestada

At what coordinate point with the graph of y = 3x - 8 intersect that of its inverse?

Respuesta :

Answer:

Point of Intersection: (-4, -4)

Step-by-step explanation:

Given the linear equation, y = 3x + 8:

We must determine its inverse, which will enable us to find the point of intersection between the given equation and its inverse.

Start by switching x and y in the given linear equation:

y = 3x + 8

x = 3y + 8

Next, subtract 8 from both sides:

x - 8 = 3y + 8 - 8

x - 8 = 3y

Multiply both sides with ⅓ to isolate y:

⅓ (x - 8) = (3y) ⅓

[tex]\displaytext\mathsf{\frac{1}{3}x\:-\frac{8}{3}\:=\:y}[/tex]

Replace y with [tex]\large{\textit{f}\:^{-1}(\textit{x}\:)}[/tex]:

[tex]\displaytext\mathsf{\textit{f}\:^{-1}(\textit{x}\:)\:=\frac{1}{3}x\:-\frac{8}{3}}[/tex] ⇒ This is the inverse function of y = 3x + 8.

Graph both equations:

Next, we must graph both equations.

Plot the y-intercept, (0, 8), and use the slope of the given linear equation, m = 3, to plot other points on the graph.

Similarly, to graph the inverse function, take the y-intercept, [tex]\displaytext\sf{(0,\:-\frac{8}{3})}[/tex], and use the slope, m = ⅓, to plot other points on the graph.

Attached is the graph of the linear equation, y = 3x + 8, and its inverse,  [tex]\displaytext\mathsf{\textit{f}\:^{-1}(\textit{x}\:)\:=\frac{1}{3}x\:-\frac{8}{3}}[/tex] , where it shows that the point of intersection occurs at point, (-4, -4).

Ver imagen djtwinx017