draw a segment of polybutadiene containing three monomer units. connect each end of the segment with a bond to one of the r groups. the r groups represent the connecting carbon atoms in the monomers adjacent to the segment. be sure to draw all hydrogen atoms.

This problem states polybutadiene as a polymer from which we have to draw three monomeric units, showing the rest of it with a general notation (R).

In this case, we need to consider that the monomeric unit in polybutadiene is 1,3-butadiene:

[tex]CH_2=CH-CH=CH_2[/tex]

And takes the polymeric notation as:

[tex]-(CH_2=CH-CH=CH_2)_n-[/tex]

Thus, since we need three monomeric units, we bind them as shown on the attached picture, which shows the 1st, 2nd and 3rd ones. Moreover, note the two R's, which stand for the rest of the polymer as a general notation.

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