(K+U)
i
=(K+U)
f
0+
2
1
kA
2
=
2
1
mv
2
+
2
1
kx
2
2
1
(6.50 N/m)(0.100 m)
2
=
2
1
m(0.300 m/s)
2
+
2
1
(6.50 N/m)(5.00×10
−2
m)
2
3.25×10
−2
J=
2
1
m(0.300 m/s)
2
+8.12×10
−3
J
giving m=
9.0×10
−2
m
2
/s
2
2(2.44×10
−2
J)
=
0.542 kg
(b) ω=
m
k
=
0.542 kg
6.50 N/m
=3.46 rad/s
Then, T=
ω
2π
=
3.46 rad/s
2π rad
=
1.81 s
(c) a
max
=Aω
2
=(0.100 m)(3.46 rad/s)
2
=
1.20 m/s
2
