Respuesta :
The motion or path of the tennis ball is the path of a projectile, which has
both vertical and horizontal motion.
The total horizontal distance traveled by the tennis ball during the entire
time it is in the air ≈ 16.514 meters.
Reasons:
The given parameters are;
The direction in which the ball is launched = 45°
The initial vertical velocity of the ball, [tex]v_y[/tex] = 9.0 m/s
The initial horizontal velocity of the ball, vₓ = 9.0 m/s
The time it takes the ball to reach the maximum height, t = 0.92 seconds after its launch
The total horizontal distance traveled, by the tennis ball is given by the formula;
[tex]\Delta d_x = \dfrac{v_1^2 \cdot \left( 2 \cdot cos(\theta) \sin(\theta)}{y} = \dfrac{2 \times v_x \times v_y}{g}[/tex]
Which gives;
[tex]\mathrm{The \ total \ distance \ travelled, \ \Delta} d_x = \dfrac{2 \times 9.0\times 9.0}{9.81} \approx 16.514[/tex]
The total horizontal distance traveled by the tennis ≈ 16.514 meters
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