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HELP PLS The current in the flashlight is 0.50 A, and the voltage is the sum of the voltages of the three individual batteries of 1.5V. What is the power delivered to the bulb of the flashlight? . If the flashlight is left on for 3.0 min, how much electric energy is delivered to the bulb?

0.11 W & 6.9 J
2.3 W & 4.1×10^2 J
1.1 W & 14J
4.5 W & 2×10^2 J

Respuesta :

Answer : 2.3 W and 4.1 x 10^2 J

I = 0.5 A
V = 3 (1.5) = 4.5 V

Power, P = IV = (0.5)(4.5) = 2.3 W

Energy = Pt = (2.3)(3.0 x 60) = 4.1 x 10^2 J