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Three gases are combined in a sealed 3.29 L sealed flask. If Ne has a partial pressure of 5.55 atm, Ar has a partial pressure of 1.79 atm and He has a partial pressure of 8.13 atm, what is the mole fraction of Ar in the flask

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Eduard22sly

The mole fraction of Ar in the flask is 0.116

We'll begin by calculating the total pressure in the flask

Partial pressure of Ne = 5.55 atm

Partial pressure of Ar = 1.79 atm

Partial pressure of He = 8.13 atm

Total pressure =?

Total pressure = 5.55 + 1.79 + 8.13

Total pressure = 15.47 atm

  • Finally, we shall determine the mole fraction of Ar.

Total pressure = 15.47 atm

Partial pressure of Ar = 1.79 atm

Mole fraction of Ar =?

Mole fraction = Partial pressure / Total pressure

Mole fraction of Ar = 1.79 / 15.47

Mole fraction of Ar = 0.116

Therefore, the mole fraction of Ar in the flask is 0.116

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