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a cylinder like the one that pictured contains a gas at 5.25 atm pressur. when the gas is allowed to expand toa final volume of 12.5 L, the pressure drops to 1.85 atm. what was the original volume of the gas

Respuesta :

Stephen46

Answer:

4.40 L

Explanation:

The original volume of the gas can be found by using the formula for Boyle's law

[tex]V_1 = \frac{P_2V_2}{P_1} \\[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

[tex]V_1 = \frac{1.85 \times 12.5}{5.25} = \frac{23.125}{5.25} \\ = 4.4047619[/tex]

We have the final answer as

4.40 L

Hope this helps you

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