Answer:
9. 1.75 m/s²; 8 s
10. (12 6/7) °/s; (10 5/7) kt/s
Step-by-step explanation:
Acceleration is the change in velocity divided by the change in time.
__
9.
(22 m/s -15 m/s)/(4 s) = 7/4 m/s² = 1.75 m/s²
The eagle's average acceleration is 1.75 m/s².
__
The relation can also be used to find the time for a given change:
a = Δv/Δt ⇒ Δt = Δv/a
Δt = (22 m/s -8 m/s)/(1.75 m/s²) = 8 s
It would take the eagle 8 seconds to go from 8 m/s to 22 m/s.
__
10.
From north to south is a direction change of 180°. Then the rate of change is ...
a = 180°/(14 s) = 12 6/7 °/s
__
From 75 knots north to 75 knots south (-75 knots, using north as a reference) the magnitude of the average acceleration is ...
|-75 kt -75 kt|/(14 s) = 150/14 kt/s = 10 5/7 kt/s
