Excited hydrogen atoms emit light in the ultraviolet at 2.47x1015Hz. What is the
energy of a single photon with this frequency?

Respuesta :

The energy of a single photon of this frequency is 1.638 × 10⁻¹⁸ J

Using Planck's equation, the energy of the photon E = hf where h = Planck's constant = 6.63 × 10⁻³⁴ Js and f = frequency of ultraviolet light = 2.47 × 10⁻¹⁵ Hz.

Substituting the values of the variables into the equation, we have

E = hf

E = 6.63 × 10⁻³⁴ Js × 2.47 × 10¹⁵ Hz.

E = 16.3761 × 10⁻¹⁹ J

E = 1.63761 × 10⁻¹⁸ J

E ≅ 1.638 × 10⁻¹⁸ J

So, the energy of a single photon of this frequency is 1.638 × 10⁻¹⁸ J

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