The reflection of the triangle JKL across the line x = 4 is equivalent to
equivalent to flipping the preimage across the line x = 4.
The correct coordinates are;
[tex]\underline{J'(7, \, -1)}[/tex]
[tex]\underline{K'(6, \, 3)}[/tex]
[tex]\underline{L'(5, -2)}[/tex]
Reasons:
The given transformation is a reflection about the line x = 4
The points of triangle JKL are J(1, -1), K(2, 3), and L(3, -2), in the line x = 4
- The coordinates of the triangle JKL following a reflection across the line x = 4, have the same y-coordinates , while the x-coordinates have the same distance magnitude to the line x = 4, but opposite sign.
Distance between x-coordinate of the point J and the line x = 4 is 4 - 1 = 3
Which gives;
Distance between x-coordinate of the point J' and the line x = 4 is 4 + 3 = 7
Therefore, the coordinate of the point J' is [tex]\underline{J'(7, \, -1)}[/tex]
Similarly, we have;
Distance between x-coordinate of the point K and the line x = 4 is 4 - 2 = 2
Distance between x-coordinate of the point K' and the line x = 4 is 4 + 2 = 6
The coordinate of the point K' is [tex]\underline{K'(6, \, 3)}[/tex]
Distance between x-coordinate of the point L and the line x = 4 is 4 - 2 = 2
Distance between x-coordinate of the point L' and the line x = 4 is 4 + 2 = 6
The coordinate of the point L' is [tex]\underline{L'(5, -2)}[/tex]
Learn more here:
https://brainly.com/question/24758871
