If 48 grams of carbon are burned in the presence of 128 grams of oxygen, the amount of carbon dioxide that forms will be ______.

A. 48 grams
B. 128 grams
C. 176 grams
D. 224 grams

Respuesta :

Answer:

C. 176 grams

Explanation:

48g / (12g/mol) = 4.0mol. Moles of Oxygen used. = 128g / (32g/mol) = 4.0mol. C + O2 => CO2. Therefore ...

C. 176 grams of carbon dioxide