If z varies directly as x and inversely as y and is equal to 4 when x and y have the values 12 and 8 respectively, what is the value of z when x is equal to 6/7 and y is equal to 5/28?

Respuesta :

Answer:

[tex]z = \frac{2}{7} [/tex] when x= [tex] \frac{6}{7} [/tex],

z= 179.2 when y= [tex] \frac{5}{28} [/tex]

Step-by-step explanation:

Let's start by writing out the two general equations for z.

Since z varies directly with x,

z= kx, where k is a constant.

Since z varies inversely with y,

[tex]z = \frac{k}{y} [/tex], where k is a constant.

When x= 12, z= 4,

4= k(12)

12k= 4

k= 4 ÷12

k= ⅓

∴ z= ⅓x

When x=[tex] \frac{6}{7} [/tex],

[tex]z = \frac{1}{3} ( \frac{6}{7} )[/tex]

[tex]z = \frac{2}{7} [/tex]

When y= 8, z= 4,

[tex]4 = \frac{k}{8} [/tex]

k= 4(8)

k= 32

[tex]∴z = \frac{32}{y} [/tex]

When y= [tex] \frac{5}{28} [/tex],

[tex]z = 32 \div \frac{5}{28} [/tex]

[tex]z = 32 \times \frac{28}{5} [/tex]

z= 179.2