contestada

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A ball is projected upward from ground level. After (t) seconds, its height in feet is
given by the function “h(t) = -16(t)^2 + 112(t)” After how many seconds will the ball reach a height of 192 ft for the first time?

Respuesta :

rspill6

Answer:  3 seconds

Step-by-step explanation:

h(t) = -16(t)^2 + 112(t)

Set h(t) = 192 feet

192 = -16(t)^2 + 112(t)

0 = -16(t)^2 + 112(t) - 192

Solve using the quadratic formula:  There are two solutions, 3 and 4 seconds.  Three seconds is the first time it reachers 192 feet,  At four seonds it's on its way down.

The function can also be graphed (attached).

Ver imagen rspill6

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