the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade is 14%.
Given, the members of the junior varsity swim team wear glasses is 55%.
And the members of junior varsity swim team who do not wear glasses and in 10th grade is 30%.
Let the total no. of members be x.
So, the members of the junior varsity swim team wear glasses (55%),will be
[tex]0.55x[/tex].
The total number of members not wearing glasses, will be
[tex]x - 0.55 x = 0.45 x[/tex].
Now, the no. of members not wearing glasses and in 10th grade will be,
[tex]\frac{0.45x\times30}{100} =0.135x[/tex]
We know that the probability of an event E, P(E) will be,
[tex]P(E)=\frac{No.\ of Favourable\ outcomes}{total \ no. \ of \ outcomes}[/tex]
So, the probability for no. of members not wearing glasses and in 10th grade will be,
[tex]P(E)=\dfrac{0.135x}{x}[/tex]
[tex]P(E)=0.135\\\\P(E)=13.5 \%[/tex]
Hence the nearest whole percent of probability is 14%.
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