Answer:
cosθ = -√(35/36)
tanθ = -1/√35
Step-by-step explanation:
We know that
sin²θ + cos²θ = 1
(1/6)² + cos²θ = 1
1 - (1/6)² = cos²θ
35/36 = cos²θ
sec θ = 1/ cosθ
1/ secθ = cos θ
Because secθ < 0, 1/ secθ would also be < 0, so cos θ < 0
cosθ = -√(35/36)
tanθ = sinθ/cosθ = (1/6)/-√(35/36)
= (1/6) / -(√35/6)
= -1/√35
