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Work Shown:
[tex]\log_6(95) = \frac{\log(95)}{\log(6)}\\\\\log_6(95) \approx \frac{1.9777236}{0.7781513}\\\\\log_6(95) \approx 2.5415669\\\\\log_6(95) \approx \boldsymbol{2.542}\\\\[/tex]
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Explanation:
In step one, I used the change of base formula which is
[tex]\log_{b}(x) = \frac{\log(x)}{\log(b)}[/tex]
For the logs on the right hand side, use any base you want; however, base 10 is the easiest in my opinion and found on many calculators.
Notice how [tex]6^{2.5415669} \approx 94.999968 \approx 95[/tex] to help confirm we have the correct evaluation.
