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A car travels 10 km southeast and then 15 km in a direction 60° north of east. Find the magnitude of the car's resultant vector.​

Respuesta :

Answer:

-10sin45+15cos60=Hor distance = 5.92 km

-10cos45+15sin60=ver distance = .429 km

resultant is sqrt(5.922+.4292)= 5.94 km at angle arctan(.429/5.92)= 1.77 degrees north of east

Step-by-step explanation:

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