Solve the inequality.
3x + 5
———- <4
2
x < [?]

Answer:
[tex]x \leqslant 1[/tex]
Step-by-step explanation:
first multiply both side by 2 to get rid of the fraction
[tex]3x + 5 \leqslant 4(2)[/tex]
[tex]3x + 5 \leqslant 8[/tex]
[tex]3x \leqslant 8 - 5[/tex]
[tex]3x \leqslant 3[/tex]
[tex]x \leqslant 1 [/tex]