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A 0.2 kg baseball with a speed of 48 m/s is struck by a bat. The ball rebounds and travels in the opposite direction at 52 m/s. The ball was in contact with the bat for only 2 ms. Find the magnitude of the force of the bat on the ball.

Respuesta :

Eduard22sly

The magnitude of the force of the bat on the ball is 10000 N

From the question given above, the following data were obtained:

  • Mass (m) = 0.2 Kg
  • Initial velocity (u) = 48 m/s
  • Final velocity (v) = 52 m/s
  • Time (t) = 2 ms = 2×10¯³ s
  • Force (F) =?

The magnitude of the force can be obtained as follow:

F = m(v + u) / t

F = 0.2 (52 + 48) / 2×10¯³

F = (0.2 × 100) / 2×10¯³

F = 20 / 2×10¯³

F = 10000 N

Thus, the magnitude of the force is 10000 N

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https://brainly.com/question/21124361

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