Answer:
x= (√2y+6/2)-1
Step-by-step explanation:
Swap sides so that all variable terms are on the left hand side.
2x^2+4x−1=y
Subtract y from both sides.
2x^2
+4x−1−y=0
Using quadratics formula:
x=-4±√4²-4*2(y-1)/2*2
x= −4±2√
2y+6/4
Next solve the equation by using either ± = subtraction or addition
I am using ± = addition. This means I add -4 to 2. From there I simplify equation.
x= (√2y+6/2)-1
Not sure if this means to find x, but I think this is what it would be.
