A survey found that in a sample of 75 families, 26 owned dogs. A survey done 15 years ago found that in a sample of 60 families, 26 owned dogs. Find the 95% confidence intervals of the true difference in the proportions.

Respuesta :

The difference in the proportions of both surveys goes from a maximum of 12.57% to a minimum of 4.76%.

Given that a survey found that in a sample of 75 families, 26 owned dogs, while a survey done 15 years ago found that in a sample of 60 families, 26 owned dogs, to find the 95% confidence intervals of the true difference in the proportions, the following calculation must be performed:

  • 75 = 100
  • 26 = X
  • 26 x 100/75 = X
  • 34.66 = X
  • 34.66 x 0.95 = 32.93
  • 34.66 x 1.05 = 36.40
  • 60 = 100
  • 26 = X
  • 26 x 100/60 = X
  • 43.33 = X
  • 43.33 x 0.95 = 41.16
  • 43.33 x 1.05 = 45.50
  • 45.50 - 32.93 = 12.57
  • 41.16 - 36.40 = 4.76

Therefore, the difference in the proportions of both surveys goes from a maximum of 12.57% to a minimum of 4.76%.

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