Answer:
15 mol
Explanation:
the balanced equation is AgNO3 + NaCl > NaNO3 + AgCl.
the stequiometry of the reactions says: one mol of silver nitrate reacts with one one mol of silver chloride to produce one mol of silver nitrate and one mol of sodium chloride.
by proportions, if you have 15 mol of AgNO3 you're gonna have 15 mol of AgCl
From 15 mol of Silver nitrate, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.
The balanced chemical reaction for the synthesis of silver chloride has been:
[tex]\rm AgNO_3\;+\;NaCl\;\rightarrow\;AgCl\;+\;NaNO_3[/tex]
From the balanced equation, since there has presence equal moles of silver nitrate and sodium chloride, the moles of silver chloride formed has been equivalent. Thus, 1 mole of silver nitrate gives 1 mole of silver chloride.
The moles of silver nitrate available are, [tex]\rm M_A_g_N_O_3=15\;mol[/tex]
The moles of silver nitrate produced can be given as:
[tex]\rm 1\;mol\;AgNO_3=1\;mol\;AgCl\\15\;mol\;AgNO_3=15\;\times\;1\;mol\;AgCl\\15\;mol\;AgNO_3=15\;mol\;AgCl[/tex]
Thus, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.
For more information about moles produced, refer to the link:
https://brainly.com/question/10606802
