Answer:
1. 5/3 is not equal to 3/5.
2. 7-(4+3) is equal to (4+3)-7
3. (x + y) + 1 is equal to x + (y + 1)
Step-by-step explanation:
1. 5/3 and 3/5 are completely different fractions and when you switch the denominator and the numerator you get a different fraction: 5/3 = 1 2/3, 3/5
2. If you solve both of them, they are equal because 7-7 = 7-7
3. This is equal due to the associative addition property, which means that when the addition of three or more numbers, the total/sum will be the same, even when the grouping of addends are changed.
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#1
[tex]\boxed{\dfrac{a}{b}=\dfrac{b}{a},a=b}[/tex]
Here 5[tex]\neq 3[/tex]
Hence inequality holds
#2
[tex]\\ \sf\longmapsto 7-(4+3)=(4+3)-7[/tex]
[tex]\\ \sf\longmapsto 7-7=7-7[/tex]
[tex]\\ \sf\longmapsto 0=0[/tex]
Equality holds
#3
[tex]\\ \sf\longmapsto (x+y)+1=x+(y+1)[/tex]
Equality holds
Done
