If a factory manufactures office chairs, and the binomial variable has mean of 10 and standard deviation of 3, based of the distribution of D
Mean of binomial distribution = np = 10
Variance of binomial distribution = npq = 9
[tex]Q = \frac{9}{np} \\\\Q = \frac{9}{10} \\\\Q = 0.9[/tex]
[tex]P = 1-q \\\\P = 0.1[/tex]
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