LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )

Answer:
k=6
?=24
Step-by-step explanation:
[tex] \frac{ln}{xz} = \frac{nm}{zy} = \frac{lm}{xy} [/tex]
[tex] \frac{36}{k + 3} = \frac{44}{k + 5} [/tex]
Now we just cross multiply
44(k+3)=36(k+5)
44k+132=36k+180
Take k-values to one side
44k-36k=180-132
8k=48
k=6
Now we can use k to find ?
[tex] \frac{44}{6 + 5} = \frac{36}{6 + 3} = \frac{?}{6} [/tex]
once simplified we get:
[tex] \frac{44}{11} = \frac{36}{9} = \frac{?}{6} [/tex]
[tex]4 = 4 = \frac{?}{6} [/tex]
in essence we know that:
[tex] \frac{4}{1} = \frac{?}{6} [/tex]
so we can cross multiply:
?=24