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The speed of a sound in a container of hydrogen at 201 K is 1220 m/s. What would be the speed of sound if the temperature were raised to 537 K? Assume that hydrogen behaves like an ideal gas.

Respuesta :

ItzBrainiac

Explanation:

T1 = 201k

T2 = 537k

C1 = 1220 m / s

C1/C2 =√(T1/T2)

C2 = C1×√(T2/T2)

C2 = 1220×√(537/201)

C2 = 1220 × √(179/67)

C2 = (1220√179)/(√69)

C2 = (1220√11993)/67 ≈ 1994.10924

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onyebuchinnaji

The speed of sound when the temperature rises is 1988.6 m/s.

Speed of sound when the temperature rises

The speed of sound when the temperature rises is calculated as follows;

[tex]C_2 = C_1 \times \sqrt{\frac{T_2}{T_1} }[/tex]

where;

  • C1 is the initial speed = 1220 m/s
  • T1 is the initial temperature = 201 K
  • T2 is the final temperature = 537 K
  • C2 is the final speed = ?

The final speed of sound is calculated as follows;

[tex]C_2 = 1220 \times \sqrt{\frac{537}{201} } \\\\C_2 = 1988.6 \ m/s[/tex]

Learn more about speed of sound with temperature here: https://brainly.com/question/14400858